-0.5x^2+40x-300=2500

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Solution for -0.5x^2+40x-300=2500 equation:



-0.5x^2+40x-300=2500
We move all terms to the left:
-0.5x^2+40x-300-(2500)=0
We add all the numbers together, and all the variables
-0.5x^2+40x-2800=0
a = -0.5; b = 40; c = -2800;
Δ = b2-4ac
Δ = 402-4·(-0.5)·(-2800)
Δ = -4000
Delta is less than zero, so there is no solution for the equation

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